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-4x^2-x+18=0
We add all the numbers together, and all the variables
-4x^2-1x+18=0
a = -4; b = -1; c = +18;
Δ = b2-4ac
Δ = -12-4·(-4)·18
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-17}{2*-4}=\frac{-16}{-8} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+17}{2*-4}=\frac{18}{-8} =-2+1/4 $
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